Accident

1958 Tybee Island mid-air collision

aircraft collision that involved the loss of a nuclear bomb

The Tybee Island mid-air collision was an incident on February 5, 1958, in which the United States Air Force lost a 7,600-pound (3,400 kg) Mark 15 nuclear bomb in the waters of Tybee Island near Savannah, Georgia, United States. During a night practice exercise, an F-86 fighter plane collided with the B-47 bomber carrying the large weapon.

The bomb was jettisoned to help prevent a crash and explosion. After several unsuccessful searches, the weapon was declared lost in Wassaw Sound off the shores of Tybee Island.

Fetching the article from Wikipedia…

Text from the Wikipedia article “1958 Tybee Island mid-air collision”, available under CC BY-SA 4.0.

Meanwhile, elsewhere

Send feedback

An idea, a mistake in the history, something that doesn’t work: every message is read.

It is about

Sent with what is on this screen (above), its address and the theme. Your browser, device, languages and rough location are read from the request itself, as any website receives them. How it is kept: privacy.