1992 United States presidential election in Oklahoma

The 1992 United States presidential election in Oklahoma took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Oklahoma was won by incumbent President George H. W. Bush (R-Texas) with 42.65 percent of the popular vote over Governor Bill Clinton (D-Arkansas) with 34.02 percent. Businessman Ross Perot (I-Texas) finished in third, with 23.01 percent of the popular vote. Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot. As of the 2024 presidential election, this is the last election in which Beckham County, Delaware County, Washita County, and Stephens County voted for a Democratic presidential candidate. This was the first time that the Democrats won the White House without Jackson County and the first time since Oklahoma statehood that a losing Republican managed to carry any of the 10 counties bordering the Red River. This is the most recent time that a Democrat has carried a majority of Oklahoma's counties in a presidential election.