1992 United States presidential election in Idaho

The 1992 United States presidential election in Idaho took place on November 3, 1992, as part of the 1992 United States presidential election. State voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

Idaho was won by incumbent President George H. W. Bush (R-Texas) with 42.03% of the popular vote over Governor Bill Clinton (D-Arkansas) with 28.42%. This marked the weakest performance by a Republican candidate in Idaho since 1964, and the smallest popular vote victory in the state since 1912, when Woodrow Wilson carried it with 32.08% of the vote. Businessman Ross Perot (I-Texas) finished as a close third, with 27.05% of the popular vote. Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot. As of the 2024 presidential election, this is the last election in which Bonner County, Clearwater County, Lewis County, and Benewah County voted for a Democratic presidential candidate.

With 27.05% of the popular vote, Idaho would prove to be Perot's fourth strongest state after Maine, Alaska and Utah. This election is the second of only two elections since Idaho's statehood in which it did not vote the same as neighboring Montana, the other being its first election 100 years prior.

In Franklin County, Clinton was a mere 22 votes away from placing 4th behind Independent candidate Bo Gritz, who himself scored 12.40%, his strongest county performance in the entire state.