The 1896 United States presidential election in Maine took place on November 3, 1896, as part of the 1896 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.
Maine voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won the state by a margin of 38.69%.
Bryan, running on a platform of free silver, appealed strongly to Western miners and farmers, but had little appeal in the Northeastern states such as Maine, despite the fact he had chosen the Maine born Arthur Sewall as running mate.
With 67.90% of the popular vote, Maine would be McKinley's fifth strongest victory in terms of percentage in the popular vote after Vermont, Massachusetts, neighboring New Hampshire and Rhode Island.
Bryan would lose Maine to McKinley again four years later and would later lose the state again in 1908 to William Howard Taft.
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Text from the Wikipedia article “1896 United States presidential election in Maine”, available under CC BY-SA 4.0.