Election

1892 United States presidential election in Washington (state)

presidential election in Washington state

The 1892 United States presidential election in Washington took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Washington participated in its first ever presidential election, having become the 42nd state on November 11, 1889. The state voted for the Republican incumbent president, Benjamin Harrison, over the Democratic candidate and former president, Grover Cleveland by a margin of 6,626 votes, or a 7.53% margin.

Fetching the article from Wikipedia…

Text from the Wikipedia article “1892 United States presidential election in Washington (state)”, available under CC BY-SA 4.0.

Meanwhile, elsewhere

Send feedback

An idea, a mistake in the history, something that doesn’t work: every message is read.

It is about

Sent with what is on this screen (above), its address and the theme. Your browser, device, languages and rough location are read from the request itself, as any website receives them. How it is kept: privacy.