Election

1892 United States presidential election in Delaware

election in Delaware

The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Despite reclaiming the presidency, Cleveland performed much worse in Delaware than he did in his 1888 re-election bid. The State shifted 10 points for Benjamin Harrison, voting for Cleveland by only 1.4 percentage points. This would be one of four states where Harrison outperformed his initial run for the presidency in 1888. The other states were New Hampshire, Georgia and, South Carolina.

This is the last election in which Delaware voted Democratic until 1912; and the last in which it voted Democratic two or more consecutive times until 1940.

Fetching the article from Wikipedia…

Text from the Wikipedia article “1892 United States presidential election in Delaware”, available under CC BY-SA 4.0.

Meanwhile, elsewhere

Send feedback

An idea, a mistake in the history, something that doesn’t work: every message is read.

It is about

Sent with what is on this screen (above), its address and the theme. Your browser, device, languages and rough location are read from the request itself, as any website receives them. How it is kept: privacy.