1880 United States presidential election in Indiana (2 November 1880)

A presidential election was held in Indiana on November 2, 1880, as part of the 1880 United States presidential election. The Republican ticket of the U.S. representative from Ohio's 19th congressional district James A. Garfield and the chair of the New York Republican Party Chester A. Arthur defeated the Democratic ticket of the major general Winfield S. Hancock and the former U.S. representative from Indiana's 2nd congressional district William H. English. Garfield defeated Hancock in the national election with 214 electoral votes.

General election

Summary

Indiana chose 15 electors in a statewide general election. Nineteenth-century presidential elections used a form of block voting that allowed voters to modify the electoral list nominated by a political party before submitting their ballots. Because voters elected each member of the Electoral College individually, electors nominated by the same party often received differing numbers of votes as a consequence of voter rolloff, split-ticket voting, or electoral fusion. This table reflects the statewide popular vote as calculated by Walter Dean Burnham in his influential study, Presidential Ballots, 1836–1892. Svend Petersen finds six more votes for Garfield, one fewer for Hancock, and 80 fewer for Weaver in Indiana.

Text from the Wikipedia article “1880 United States presidential election in Indiana”, available under CC BY-SA 4.0.

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Text from the Wikipedia article “1880 United States presidential election in Indiana”, available under CC BY-SA 4.0.

1880 United States presidential election in Indiana

General election

Summary

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General election

Summary