A presidential election was held in Rhode Island on November 6, 1844, as part of the 1844 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Rhode Island by a margin of 19.97%.
With 59.55% of the popular vote, Rhode Island would prove to be Henry Clay's strongest state in the nation.
Fetching the article from Wikipedia…
Text from the Wikipedia article “1844 United States presidential election in Rhode Island”, available under CC BY-SA 4.0.